(x-3/4x+4)(x^2-x-2/x+2)

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Solution for (x-3/4x+4)(x^2-x-2/x+2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x-((3/4)*x)+4)*(x^2-x-(2/x)+2) = 0

(x+(-3/4)*x+4)*(x^2-x-2*x^-1+2) = 0

(1/4*x+4)*(x^2-x-2*x^-1+2) = 0

x^2-x-2*x^-1+2 = 0

x^2-x-2*x^-1+2

x^2-x^-1*(x^2+2)+2

(1-x^-1)*(x^2+2)

(1/4*x+4)*(1-x^-1)*(x^2+2) = 0

( 1-x^-1 )

-1*x^-1 = -1 // : -1

x^-1 = 1

-1 < 0

1/(x^1) = 1 // * x^1

1 = 1*x^1 // : 1

1 = x^1

x = 1

( 1/4*x+4 )

1/4*x+4 = 0 // - 4

1/4*x = -4 // : 1/4

x = -4/1/4

x = -16

( x^2+2 )

1*x^2 = -2 // : 1

x^2 = -2

x in { 1, -16 }

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